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\int\limits^3_2 2{x} \, dx* (3x)/(2)

User Ndoogan
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1 Answer

5 votes

Answer:

We can solve this integral using the u-substitution method.

Let u = 3x, then du/dx = 3 and dx = du/3.

Substituting these values, we get:

∫2x * 2/3x dx = ∫4/3 du

Integrating, we get:

= (4/3)u + C

Substituting back u = 3x, we get:

= (4/3)(3x) + C

= 4x + C

Therefore, the solution to the integral ∫2x * 2/3x dx is 4x + C.

User Wedocando
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