Answer:
We can solve this integral using the u-substitution method.
Let u = 3x, then du/dx = 3 and dx = du/3.
Substituting these values, we get:
∫2x * 2/3x dx = ∫4/3 du
Integrating, we get:
= (4/3)u + C
Substituting back u = 3x, we get:
= (4/3)(3x) + C
= 4x + C
Therefore, the solution to the integral ∫2x * 2/3x dx is 4x + C.