Question

The displacement of two interfering light waves are y1=4sinwt and y2=3sin(wt+π/2)The amplitude of the resultant wave is a. 5 b. 7 c. 1 d. 0

Answer 1

Step-by-step explanation:

Amplitude of first wave a1=4

Amplitude of second wave a2=3

Angle between two waves =Π/2

Resultant amplitude=
`\sqrt{a_(1) ^(2)+a_(2) ^(2) +2a_(1) a_(2) cos\alpha }`

=
`\sqrt{4^(2)+3^(2) +2*4*3*cos90 }`

=5

Answer is a