Question

What is the vertex for the following quadratic function?
x^2-4x-6

Answer 1

vertex = (2, - 10 )

Explanation:

given a quadratic function in standard form

ax² + bx + c ( a ≠ 0 )

then the x- coordinate of the vertex is

`x_(vertex)` = -
`(b)/(2a)`

x² - 4x - 6 ← is in standard form

with a = 1 and b = - 4 , then

`x_(vertex)` = -
`(-4)/(2)` = 2

substitute x = 2 into the function for corresponding y- coordinate

2² - 4(2) - 6

= 4 - 8 - 6

= - 10

vertex = (2, - 10 )