Question

Given that -3/2 is one of the root of the equation 2y^2+6y+p=0, find the value of p

Answer 1

p =
`(9)/(2)`

Explanation:

given y = -
`(3)/(2)` is a root of the equation , then this value makes the equation true.

substitute y = -
`(3)/(2)` into the equation and solve for p

2( -
`(3)/(2)` )² + 6(-
`(3)/(2)` ) + p = 0

2(
`(9)/(4)`) - 9 + p = 0

`(9)/(2)` -
`(18)/(2)` + p = 0

-
`(9)/(2)` + p = 0 ( add
`(9)/(2)` to both sides )

p =
`(9)/(2)`