Answer:
a = 4m kgm/s & b. v = 4 m/s
Step-by-step explanation:
a:
A is approaching in the opposite direction of B
So let's take the velocity of A as negative.
Here we'd need to solve this using conservation of momentum.
m1u1 + m2u2 = m1v1 + m2v2
So initial momentum = (m X (-4)) + (m X 8) = -4m + 8m = 4m
b:
After collision sphere A stops, so v = 0 for sphere A
Using the conservation of momentum formula, we get
(m X (-4)) + (m X 8) = (0 X m) + (m X v) [let the final velocity of B be v]
⇒ 4m = vm
⇒ v = 4 m/s