Question

Write a sine function that has an amplitude of 5, a midline of 4 and a period of 3/2

Answer 1

Note that in any sine function :

`y=A\sin (B(x+C))+D`

Amplitude = A

Verical Shift or midline = D

Period = (2π)/B

Horizontal or Phase Shift = C

From the given,

since we dont have any horizontal shift, C = 0.

Amplitude = 5, so A = 5

Midline = 4, so D = 4

and

Period = 3/2, so equating it to (2 π)/B

`(3)/(2)=(2\pi)/(B)`
`B=(4\pi)/(3)`

Now, substituting the values obtained, the sine function will be :

`y=5\sin ((4\pi)/(3)x)+4`