Given the table:
Outcome Probability
1 0.2
2 0.6
3 0.2
Let A be the event "the outcome less than or equal to 2.
Let B be the event "the outcome is a divisor of 3.
Let's find P(A ∩ B).
To find P(A ∩ B) let's first find P(A) and P(B).
Numbers less than or equal to 2 = 2 and 1
Outcomes less than or equal to 2 = P(2) or P(1)
Probability the outcome is less than or equal to 2 = P(A) = 0.2 + 0.6 = 0.8
Divisor of 3 = 1 and 3
Outcome is a divisor of 3 = P(1) and P(3)
Probability the outcome is a divisor of 3 = P(B) = 0.2 x 0.2 = 0.04
To find P(A ∩ B), we have:
P(A ∩ B) = P(A) x P(B) = 0.04 x 0.8 = 0.032
ANSWER:
0.032