Question

Please help i really need ittt!!!!!!!!!!!!!!!!!!!!!!!!!

A 2.5 m ramp is used to load a truck 1.0 m off of the ground. A man uses 600 N of force to load a box weighing 1200 N. What is the efficiency of the ramp? What is the mechanical advantage of the ramp?

Answer 1

To find the efficiency of the ramp, we need to compare the work output to the work input. Work input is the force applied to the ramp multiplied by the distance over which the force is applied, and work output is the weight of the box multiplied by the distance it is lifted.

The force applied to the ramp is 600 N, and the distance over which it is applied is the length of the ramp, which is 2.5 m. So the work input is:

work input = force x distance = 600 N x 2.5 m = 1500 J

The weight of the box is 1200 N, and the distance it is lifted is 1.0 m (the height of the truck). So the work output is:

work output = weight x distance = 1200 N x 1.0 m = 1200 J

The efficiency of the ramp is the ratio of work output to work input:

efficiency = work output / work input = 1200 J / 1500 J = 0.8 = 80%

So the efficiency of the ramp is 80%.

To find the mechanical advantage of the ramp, we need to compare the output force to the input force. The output force is the weight of the box, which is 1200 N. The input force is the force applied to the ramp, which is 600 N.

So the mechanical advantage of the ramp is:

mechanical advantage = output force / input force = 1200 N / 600 N = 2

So the mechanical advantage of the ramp is 2.