Question

The sum of an odd integer and 4 times the next consecutive integer is 63

Find the value of the greater integer

Answer 1

the greater integer is "y", which is 13.

Explanation:

Let's call the odd integer "x", and the next consecutive integer "y". Since "y" is the next consecutive integer after "x", we know that:

y = x + 2

We are told that the sum of "x" and 4 times "y" is 63. We can set up an equation to represent this:

x + 4y = 63

Now we can substitute the expression for "y" in terms of "x" into this equation:

x + 4(x + 2) = 63

Simplifying this equation, we get:

x + 4x + 8 = 63

5x + 8 = 63

Subtracting 8 from both sides, we get:

5x = 55

Dividing both sides by 5, we get:

x = 11

So the odd integer is 11. We can use the expression for "y" in terms of "x" to find the next consecutive integer:

y = x + 2 = 11 + 2 = 13

Therefore, the greater integer is "y", which is 13.

Answer 2

13

Explanation:

there is an interval of 2 between consecutive odd numbers

let n and n + 2 be the 2 consecutive integers , then

n + 4(n + 2) = 63 , that is

n + 4n + 8 = 63

5n + 8 = 63 ( subtract 8 from both sides )

5n = 55 ( divide both sides by 5 )

n = 11

then larger integer is n + 2 = 11 + 2 = 13