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the pressure on 2.5L of antistatic gas is changed from 760 mmHg to 304mmHg .What is the final volume if the temperature remains the same?

User Muljayan
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Answer:

combined gas law, which relates the pressure, volume, and temperature of a gas. The combined gas law is given by:

P1V1/T1 = P2V2/T2

Where P1, V1, and T1 are the initial pressure, volume, and temperature, respectively, and P2, V2, and T2 are the final pressure, volume, and temperature, respectively.

In this problem, the temperature remains the same, so we can simplify the combined gas law to:

P1V1 = P2V2

Substituting the given values into the equation, we get:

760 mmHg × 2.5 L = 304 mmHg × V2

Solving for V2, we get:

V2 = (760 mmHg × 2.5 L) / 304 mmHg

V2 ≈ 6.26 L

Therefore, the final volume of the gas is approximately 6.26 L.

User Rich Hoffman
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