Answer:
The percent composition by mass of a component in a mixture is given by:
percent composition = (mass of component / total mass of mixture) x 100%
In this case, the component is sucrose, and the total mass of the mixture is the sum of the mass of sucrose and the mass of water. We have:
mass of sucrose = 4.6 g mass of water = 72.9 g total mass of mixture = mass of sucrose + mass of water = 4.6 g + 72.9 g = 77.5 g
Substituting these values into the formula, we get:
percent composition of sucrose = (4.6 g / 77.5 g) x 100% = 5.94%
Rounding to the tenths place, we get:
percent composition of sucrose ≈ 5.9%
Therefore, the percent composition of sucrose in the mixture is approximately 5.9%.
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