147k views
3 votes
URGENT HELP NEEDED!!!

Two balls are rolling in the positive x-direction. Ball A has a mass of 1 kg, and rolls with velocity vA=4 m/s. Ball B has a mass of 2 kg, and rolls with velocity vB=3 m/s. If those balls were to collide, which of the following outcomes would conserve momentum?


vA=6 m/s, vB=2 m/s

vA=3 m/s, vB=4 m/s

vA=3.5 m/s, vB=3.5 m/s

vA=−2 m/s, vB=6 m/s

vA=10 m/s, vB=0 m/s

vA=−4 m/s, vB=−3 m/s

User Tillebeck
by
8.8k points

1 Answer

2 votes

Answer:

Let's check each option to see if it conserves momentum:

Option 1: p_after = 1 kg * 6 m/s + 2 kg * 2 m/s = 10 kg m/s (conserves momentum)

Option 2: p_after = 1 kg * 3 m/s + 2 kg * 4 m/s = 11 kg m/s (doesn't conserve momentum)

Option 3: p_after = 1 kg * 3.5 m/s + 2 kg * 3.5 m/s = 10.5 kg m/s (doesn't conserve momentum)

Option 4: p_after = 1 kg * (-2 m/s) + 2 kg * 6 m/s = 10 kg m/s (conserves momentum)

Option 5: p_after = 1 kg * 10 m/s + 2 kg * 0 m/s = 10 kg m/s (conserves momentum)

Option 6: p_after = 1 kg * (-4 m/s) + 2 kg * (-3 m/s) = -10 kg m/s (doesn't conserve momentum)

Therefore, options 1, 4, and 5 conserve momentum.

Step-by-step explanation:

User Aleksandr Larionov
by
7.8k points