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14 votes
Please help me

find

\sin(2x + (5\pi)/(4) )
if

\tan(x) = (2)/(3)




User Emerssso
by
6.3k points

1 Answer

3 votes

Answer:

-17√2 /26 or -0.9247 to the nearest ten thousandth.

Explanation:

The hypotenuse of the right triangle in which tan x = 2/3 is √(2^2 + 3^2)

= √13 so sin x = 2/√13 and cos x = 3/√13

sin2x = 2sinxcos

= 2* 2/√13 * 3/√13

= 12/13.

cos2x = cos^2x - sin^2x

= 9/13 - 4/13

= 5/13.

sin(2x + 5π/4)

= sin2x cos5π/4 + cos2x sin5π/4

= 12/13 * -1/√2 + 5/13 * -1/√2

= -12 / 13√2 - 5 / 13√2

= -17/13√2

= -17√2 /26.

User Aatif Farooq
by
4.9k points