63.2k views
14 votes
Please help me

find

\sin(2x + (5\pi)/(4) )
if

\tan(x) = (2)/(3)




User Emerssso
by
9.0k points

1 Answer

3 votes

Answer:

-17√2 /26 or -0.9247 to the nearest ten thousandth.

Explanation:

The hypotenuse of the right triangle in which tan x = 2/3 is √(2^2 + 3^2)

= √13 so sin x = 2/√13 and cos x = 3/√13

sin2x = 2sinxcos

= 2* 2/√13 * 3/√13

= 12/13.

cos2x = cos^2x - sin^2x

= 9/13 - 4/13

= 5/13.

sin(2x + 5π/4)

= sin2x cos5π/4 + cos2x sin5π/4

= 12/13 * -1/√2 + 5/13 * -1/√2

= -12 / 13√2 - 5 / 13√2

= -17/13√2

= -17√2 /26.

User Aatif Farooq
by
7.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories