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inverse trig ratio can someone pls answer the rest of these i don’t understand them answers are already there but i need to see how they are done

inverse trig ratio can someone pls answer the rest of these i don’t understand them-example-1
User Nanotek
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We're given the angle measure to be 46 for No. 8. The length of 1 leg is x and the hypotenuse is 28.

We can use cosine to solve this. Since cosine is adjacent over hypotenuse, we can do cos(46) = x/28. Cross multiply to get cos(46)*28 = x. That solves to be 19.5

Using this principle allows us to solve the other ones. I'll let you figure them out.

TLDR: We can use the definition of trig functions to plug in what we know and place variables where we don't have enough information to find the length of a side.

User Masnad Nihit
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