Question

How many grams of Na form when 100.0 grams NaN3 react ?

Answer 1

35.4g

Step-by-step explanation:

Na = 23 g/mol

NaN3 = 23 + 3(14) = 65 g/mol

2NaN3 -> 3N2 + 2Na

=> 2 moles of NaN3 will produce 2 moles of Na

or 1 mole of NaN3 will produce 1 mole of Na

the moles of NaN3 with mass of 100.0 g is 100/65 moles

so mass of Na is: (100/65) x 23 = 35.38 or 35.4g