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45.0J of work is done on a 1.50kg ball at rest. What is the velocity of the ball?

30.0m/s
5.48m/s
60.0m/s
7.75m/s

User Diemauerdk
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1 Answer

3 votes

Answer:

7.75 m/s.

Step-by-step explanation:

We can use the work-energy principle to solve this problem. The principle states that the work done on an object is equal to the change in its kinetic energy:

W = ΔK

where W is the work done, ΔK is the change in kinetic energy.

In this case, the work done on the ball is 45.0 J. Since the ball is initially at rest, its initial kinetic energy is zero. Therefore, the change in kinetic energy is:

ΔK = Kf - Ki = 1/2 mv^2 - 0

where Kf is the final kinetic energy, Ki is the initial kinetic energy, m is the mass of the ball, and v is its velocity.

Substituting the given values, we get:

45.0 J = 1/2 (1.50 kg) v^2

Solving for v, we get:

v^2 = (2 x 45.0 J) / (1.50 kg)

v^2 = 60.0

v = √60.0

v ≈ 7.75 m/s

Therefore, the velocity of the ball is approximately 7.75 m/s.

User Frenchbaguette
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