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Calculate the molarity of 0.5 moles NaHCO3 in 1,892 mL of solution.

Calculate the molarity of 0.5 moles NaHCO3 in 1,892 mL of solution.-example-1
User Eswar
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1 Answer

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Answer: 0.264 M

Explanation: the first step is to transfer mL to L, which can be done with the conversion rate of 1000mL = 1L.

This gives you 1.892 L.

Then you divide the mols by the liters, since Molarity (M) =Mol/L.

0.5/1.892 = M

M = 0.2642706131

It can then be rounded to the proper amount of significant figures. I used 3.

M = 0.264

User Shanlodh
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