Answer:0.216 kg
Step-by-step explanation:
The volume of a sphere is given by the formula:
V = (4/3)πr^3
where r is the radius of the sphere. Since the diameter of the iron sphere is 6.6 cm, its radius is half of that or 3.3 cm (0.033 m).
The volume of the sphere is:
V = (4/3)π(0.033 m)^3
V = 2.76 x 10^-5 m^3
The density of iron is 7850 kg/m^3. We can use the density formula to find the mass of the sphere:
density = mass / volume
mass = density x volume
mass = 7850 kg/m^3 x 2.76 x 10^-5 m^3
mass = 0.216 kg
Therefore, the mass of the solid iron sphere is 0.216 kg.