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You throw a water ballon straight up with a velocity of 12 m/s. What is its maximum height

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Answer:7.35 meters

Step-by-step explanation:

Assuming that air resistance is negligible, we can use the kinematic equation:

h = (v^2)/(2g)

where h is the maximum height, v is the initial velocity, and g is the acceleration due to gravity (9.8 m/s^2).

Substituting the given values:

h = (12^2)/(2 × 9.8)

h = 7.35 meters

Therefore, the maximum height of the water balloon is approximately 7.35 meters.

User Christopher Orr
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