Question

The current through a motor is 210 A. If a battery keeps a 12.0 V potential difference across the motor, what electric energy is delivered to the motor in 10.0 s?

Answer 1

Given:

the current through motor is

`I=210\text{ A}`

The potential of the battery is

`V=12\text{ V}`

The time is

`t=10\text{ s}`

Required: the energy delivered to the motor in 10 sec is?

Explanation:

first, we calculate the power delivered to the motor.

The power is given by

`P=VI`

Plugging all the values in the above relation, we get:

`\begin{gathered} P=12\text{ V}*210\text{ A} \\ P=2520\text{ watt} \end{gathered}`

The energy delivered to the motor is given by

`E=Pt`

Plugging all the values in the above relation, we get:

`\begin{gathered} E=2520\text{ w}*10\text{ s} \\ E=25200\text{ J} \\ \end{gathered}`

Thus, the energy delivered to the motor is 25200 J.