117k views
3 votes
A student solved the equation x²+ 5x -60 = 5x +4. The student's work is shown below.

Determine if the student made an error. If so, explain their error AND solve for the correct solutions.

A student solved the equation x²+ 5x -60 = 5x +4. The student's work is shown below-example-1
User Korun
by
8.0k points

2 Answers

5 votes

Answer: x = ±8

Explanation:

The given equation is:

x² + 5x - 60 = 5x + 4

The student's work shows that they simplified the equation correctly to:

x² - 64 = 0

However, their factorization of the resulting equation is incorrect. Factoring x² - 64 using difference of squares we get:

(x + 8)(x - 8) = 0

So, the solutions for x are x = -8 and x = 8. The student's solutions of x = ±32 are incorrect.

Therefore, the student made an error in factoring the equation, and the correct solutions for x are x = -8 and x = 8.

User Janx
by
7.5k points
3 votes

Answer:

x = -8, 8

Explanation:

The student did make an error. When factoring
x^2-64, they used incorrect factors. Using FOIL method, the students factored equation would become
x^2 +32x-32x-1024 = x^2-1024, which is not
x^2-64.

Instead, the factors 8 and -8 should be used.


x^(2) +5x-60=5x+4\\x^2 +5x - 64=5x\\x^2-64=0\\(x+8)(x-8)=0\\x=-8, 8

User Abdul Manan
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories