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2 votes
D(t) = 16t2 -23t + 18

User Markinhos
by
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2 Answers

4 votes

Answer:

t = 23/32 + (i sqrt(623))/32 or t = 23/32 - (i sqrt(623))/32

Explanation:

Solve for t:

16 t^2 - 23 t + 18 = 0

Divide both sides by 16:

t^2 - (23 t)/16 + 9/8 = 0

Subtract 9/8 from both sides:

t^2 - (23 t)/16 = -9/8

Add 529/1024 to both sides:

t^2 - (23 t)/16 + 529/1024 = -623/1024

Write the left hand side as a square:

(t - 23/32)^2 = -623/1024

Take the square root of both sides:

t - 23/32 = (i sqrt(623))/32 or t - 23/32 = -(i sqrt(623))/32

Add 23/32 to both sides:

t = 23/32 + (i sqrt(623))/32 or t - 23/32 = -(i sqrt(623))/32

Add 23/32 to both sides:

Answer: t = 23/32 + (i sqrt(623))/32 or t = 23/32 - (i sqrt(623))/32

User Fabian Sierra
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7 votes
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User Frank Wong
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