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How can you use the factored form of the polynomial x^4 - 2x^3 - 9x^2 + 18x = x(x-3)(x+3)(x-2) to find the x intercepts of the graph of the function?

How can you use the factored form of the polynomial x^4 - 2x^3 - 9x^2 + 18x = x(x-example-1
User Binks
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1 Answer

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Answer:

see explanation

Explanation:

the x- intercepts are the values of x on the x- axis where the graph crosses the x- axis.

On the x- axis the y- coordinate of any point is zero.

Set the factored form of the polynomial to zero and solve for x

x(x - 3)(x + 3)(x - 2) = 0

equate each factor to zero and solve for x

x = 0

x - 3 = 0 ⇒ x = 3

x + 3 = 0 ⇒ x = - 3

x - 2 = 0 ⇒ x = 2

the x-intercepts are then x = - 3, x = 0, x = 2, x = 3

these can be confirmed from the graph of the polynomial

User Elytscha Smith
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