The molar mass of AgNO3 is 169.87 g/mol, and the molar mass of AgCl is 143.32 g/mol. We can use these values to calculate the theoretical yield of AgCl:
First, we need to determine the limiting reagent in the reaction. We have 16.0 g of AgNO3, which is:
16.0 g AgNO3 x (1 mol AgNO3/169.87 g AgNO3) = 0.0942 mol AgNO3
If we assume an excess of BaCl2, we can calculate the maximum amount of AgCl that can be produced:
0.0942 mol AgNO3 x (2 mol AgCl/2 mol AgNO3) x (143.32 g AgCl/1 mol AgCl) = 26.99 g AgCl (theoretical yield)
However, only 10.0 g of AgCl were recovered. We can calculate the percent yield of the reaction as follows:
Percent yield = (actual yield/theoretical yield) x 100%
Percent yield = (10.0 g AgCl/26.99 g AgCl) x 100% = 37.05%
Therefore, the percent yield of the reaction is 37.05%.