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In a laboratory 24 grams of propane (C3H8) is combusted in a sealed container with 55 grams of oxygen. 19.65 mL of water is collected. What is the percent yield for this reaction?

***you must write a balanced equation first
****density of water is 1g/1mL
PLEASE HELP

User HeyZiko
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1 Answer

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Answer:

25.0 grams of propane (C3H8) reacts with 25.0 grams of oxygen according to the following equation: C3H8 (g) + 5O2 (g) arrow 3CO2 (g) +...

Step-by-step explanation:

User Gamen
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