Answer:
Explanation:
Solution
Distance between two points =
(x 2−x 1) 2+(y 2 −y 1) 2
Given, one point =(2,−3)
Let, other point =(10,b)
absicca is x cordinate
(10−2) 2+(b+3) 2=108 2+(b 2+9+6b)=10
Squaring both sides, we get
64+b
2
+9+6b=100
(b+3)
2
=36
∴ b+3=6 and b+3=−6
∴ b=3 and b=−9