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Find angle A on a triangle when A(5x-1) B is unknown and C(2x)?

Find angle A on a triangle when A(5x-1) B is unknown and C(2x)?-example-1
User Abou Menah
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1 Answer

4 votes

Answer:

∠A = 64°

Explanation:

You have a triangle inscribed in a semicircle with acute angles marked A=(5x-1)° and C=(2x)°.

Right triangle

A triangle inscribed in a semicircle is a right triangle. (You know that because angle B is half the measure of 180° arc AC.) That means the two marked angles total 90°:

(5x -1) +(2x) = 90

7x = 91

x = 13

Then angle A is ...

A = (5·13 -1)° = (65 -1)° = 64°

The measure of angle A is 64°.

__

Check:

C = (2x)° = (2·13)° = 26°

Then A+C = 64° +26° = 90°, as required.

User Diego Basch
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