Question

The function
`f(t) = 1600(0.93) ^(10t)`represents the change in a quantity over t decades. What does the constant 0.93 reveal about the rate of change of the quantity?

Answer 1

Given the function;

`f(t)=1600\cdot(0.93)^(10t)`

The function shows exponential decay with a rate of 0.93

So, the quantity will decrease each year with the rate of 0.93