Solve 9x^2-6x+1=2 using the square root property. Round to the nearest hundredth if necessary.

asked Feb 22, 2024 95.3k views

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$9x^2-6x+1=2 \iff (3x)^2-2(3x)+1=2\\$

(3x - 1)^2 = 2

$3x-1=-√(2) \iff 3x = 1 - √(2) \implies x_(1) = (1-√(2) )/(3)\\$

$3x-1=√(2) \iff 3x = 1 + √(2) \implies x_(2) = (1+√(2) )/(3)\\$

$(-0.14, \ 0.8)$

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