Question

How do u solve 6=×+3_2

Answer 1

`6=(x+3)/(2)`

To solve the equation, we should isolate x on one side and the numerical term on the other side

So we have to multiply both sides by 2 to cancel the denominator 2 from the right side

`\begin{gathered} 6*2=((x+3))/(2)*2 \\ 12=x+3 \end{gathered}`

Now want to move 3 from the right side to the left side

Subtract 3 from both sides

`\begin{gathered} 12-3=x+3-3 \\ 9=x \end{gathered}`

The solution is x = 9