Question

The angle of elevation of the top of the building at a distance of 55 m from its foot on a

horizontal plane is found to be 60°. Find the height of the building rounded to the nearest
tenth of a meter.
The height of the building is _______ meters.

Need help

Answer 1

Let's call the height of the building "h". We can use trigonometry to solve for "h" using the angle of elevation and the horizontal distance from the foot of the building to the point where the angle of elevation is measured.

In this case, we have a right triangle with the height of the building as one leg, the horizontal distance as the adjacent leg, and the angle of elevation as the angle opposite the height. So we can use the tangent function:

tan(60°) = h/55

Solving for "h", we get:

h = 55 tan(60°)

h ≈ 95.1

Rounded to the nearest tenth of a meter, the height of the building is approximately 95.1 meters.