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A bakery makes cylindrical mini muffins that measure 2 inches in diameter and one and one fourth inches in height. If each mini muffin is completely wrapped in paper, then at least how much paper is needed to wrap 6 mini muffins? Approximate using pi equals 22 over 7.

A. 14 and 1 over 7 in2
B. 23 and 4 over 7 in2
C. 47 and 1 over 7 in2
D. 84 and 6 over 7 in2

User Amalgamate
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1 Answer

1 vote

Answer:

D. 84 and 6 over 7 in2

Explanation:

The surface area of the cylindrical mini muffin can be calculated as follows:

Surface area = 2πr^2 + 2πrh

where r is the radius of the circular base and h is the height of the cylinder.

Given that the diameter of the mini muffin is 2 inches, the radius can be calculated as 1 inch (since radius = diameter / 2).

So, r = 1 inch and h = 1 and 1/4 inches.

Substituting these values into the surface area formula, we get:

Surface area = 2 x (22/7) x 1^2 + 2 x (22/7) x 1 x (5/4)

= (44/7) + (55/7)

= 99/7

≈ 14.14 square inches

Therefore, the surface area of 1 mini muffin is approximately 14.14 square inches.

To wrap 6 mini muffins, we need to multiply the surface area of 1 mini muffin by 6:

Surface area of 6 mini muffins = 6 x 14.14

≈ 84.84 square inches

Rounding off to one decimal place, the minimum amount of paper needed to wrap 6 mini muffins is approximately 84.8 square inches, which is closest to option D, 84 and 6/7 in^2.

User AndrzejJ
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