Question

Alaxin (CH)no, is a newly discovered drug for the treatment of malaria. Determine the molecular formula of Alaxin if its relative atomic mass is 284. (H = 1; C = 12; 0 = 16)​

Answer 1

Step-by-step explanation:

Empirical formula:

C=5, H=8, O=5

Total mass = 5(12) + 8(1) + 5(16) = 120 + 8 + 80 = 208

Empirical formula mass = 208

Next, we can calculate the molecular formula using the given relative molecular mass and the empirical formula mass.

Relative molecular mass = 284

Empirical formula mass = 208

n = Relative molecular mass / Empirical formula mass

n = 284 / 208

n = 1.365

We need to round off the value of n to the nearest integer.

n ≈ 1

Therefore, the molecular formula of Alaxin is the same as the empirical formula: C5H8O5.