Question

Given the reaction,

2 H2 (g) + 02 (g) -> 2 H20 (g)
Find the mass of water produced from 6.4 L H2 at STP if all of it reacts. Round your answer to two decimal places.

Answer 1

First, we need to find the number of moles of H2 present in 6.4 L at STP (Standard Temperature and Pressure), which is 0°C and 1 atm pressure. At STP, one mole of any gas occupies 22.4 L of volume.

So, the number of moles of H2 present in 6.4 L at STP is:

6.4 L H2 x (1 mol H2/22.4 L H2) = 0.286 mol H2

From the balanced chemical equation, we know that 2 moles of H2 produce 2 moles of H2O.

So, 0.286 mol H2 will produce (2/2) x 0.286 = 0.286 mol H2O.

Finally, we can use the molar mass of water (18.015 g/mol) to find the mass of water produced:

0.286 mol H2O x 18.015 g/mol = 5.16 g H2O

Therefore, the mass of water produced from 6.4 L H2 at STP is 5.16 g.