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In ΔIJK, i = 2. 1 inches, � m∠J=103° and � m∠K=13°. Find the length of k, to the nearest 10th of an inch

User NSP
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1 Answer

5 votes

Answer:

k ≈ 0.5 in

Explanation:

You want the measure of side k in ∆IJK with i = 2.1 in, J = 103°, K = 13°.

Law of sines

The angle opposite the side of interest is ...

I = 180° -J -K = 180° -103° -13° = 64°

The law of sines tells us side lengths are proportional to the sine of the opposite angle:

i/sin(I) = k/sin(K)

k = i·sin(K)/sin(I) = (2.1 in)·sin(13°)/sin(64°) ≈ 0.5 in

The length of k is about 0.5 inches.

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In ΔIJK, i = 2. 1 inches, � m∠J=103° and � m∠K=13°. Find the length of k, to the nearest-example-1
In ΔIJK, i = 2. 1 inches, � m∠J=103° and � m∠K=13°. Find the length of k, to the nearest-example-2
User Nok Imchen
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7.7k points