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HELP PLS HURRY...............................................................................

HELP PLS HURRY...............................................................................-example-1

2 Answers

4 votes

Answer:

-1/10

Explanation:

To find:-

  • The slope of the line passing through the points (-3,-7/2) and (2,-4) .

Answer:-

We are here given two points and we are interested in finding out the slope of the line passing through the points. Slope can be calculated by using;


:\implies \sf \boxed{\pink{\sf m =(y_2-y_1)/(x_2-x_1)}} \\

where ,

  • (x1,y1) and (x2,y2) are the coordinates of the two points.

Also , we can write the coordinate (-3,-7/2) as (-3,-3.5) .

So on substituting the respective values, we have;


:\implies \sf m =(-3.5- (-4))/(-3-2) \\


:\implies \sf m = (-3.5+4)/(-5) \\


:\implies \sf m =(0.5)/(-5) \\


:\implies \sf m = (1)/(2(-5))\\


:\implies \sf m =(1)/(-10) \\


:\implies \sf \pink{ m =(-1)/(10)} \\

Hence the slope of the line is -1/10 .

User Mflaming
by
7.8k points
1 vote

Answer:

  • C) - 1/10

--------------------------------

Given two points:


  • (-3, -7/2}) \ and \ (2, -4)

Find the slope of the line containing these points.

Slope equation:


  • m=(y_2-y_1)/(x_2-x_1)

Substitute coordinates and find the slope:


  • m=(-4-(-7/2))/(2-(-3))=(-4+7/2)/(2+3)=(-1/2)/5=-1/10
User Rafael Shkembi
by
7.2k points