Question

HELP ASAP

Carissa also has a sink that is shaped like a half-sphere. The sink has a volume of 4500/3 πin3. One day, her sink clogged. She has to use one of two conical cups to scoop the water out of the sink. The sink is completely full when Carissa begins scooping.
(a) One cup has a diameter of 6 in. and a height of 14 in. How many cups of water must Carissa scoop out of the sink with this cup to empty it? Round the number of scoops to the nearest whole number.
(b) One cup has a diameter of 10 in. and a height of 12 in. How many cups of water must she scoop out of the sink with this cup to empty it? Round the number of scoops to the nearest whole number.

Answer 1

By taking the quotient between the volume of the sink and the volume for each cone, we will see that both of your answers are correct.

How many coops does Carissa need to scoop out in each case?

First, we know that the sink has a volume V =

(2000/3)*pi in^3

A) First, she uses a cone of a diameter of 4 in and a height of 8 in.

Remember that the volume of a cone of diameter D and height H is:

V = pi*(D/2)^2*H/3

Then this cone has a volume of:

V = (pi*/3)*(4in/2)^2*8in = (pi/3) 32 in^3

The number of scoops needed to completely remove the water out of the sink is given by the quotient between the two volumes, it is:

Rounding it, we get 63, so she needs to scoop 63 times.

B) This time the diameter is 8 in and the height 8in, so the volume of the cone is:

V" = (pi/3)*(8in/2)^2*8in = (pi/3)*128 in^3

This time, she needs to scoop:

Rounding to the next number we get 16, she needs to scoop 16 times.

So both the answers are correct :)