Question

When an airplane accelerates down a runway at 3.20 m/s2 to 5.41 m/s2 for 28 s until is finally lifts off the ground calculate its acceleration before it takes off.

Answer 1

-87.786

Explanation:

Given:

Acceleration 1 = 3.20 m/s²

Acceleration 2 = 5.41 m/s²

Time = 28 s

To find: Acceleration before takeoff

Initial velocity = Average acceleration x time + 0.5 x acceleration 1 x time²

Initial velocity = 3.20 m/s² x 28 s + 0.5 x 3.20 m/s² x (28 s)²

Initial velocity = 2460.8 m

Acceleration before takeoff = (0 m/s - 2460.8 m/s) / 28 s

Acceleration before takeoff = -87.886 m/s²

Therefore, the acceleration before takeoff is -87.886 m/s².