Question

Find the equation of a line passing through the points (3,-4) and (1,2)

Answer 1

y=\\eg;[3]x+5

Step-by-step explanation:

Answer 2

Step-by-step explanation:

The equation of a line in slope-intercept form is:

`y=mx+b`

Where m is the slope and b is the y-intercept.

The formula for the slope of a line with points (x1, y1) and (x2, y2) is:

`m=(y_1-y_2)/(x_1-x_2)`

In this case the slope is:

`m=(-4-2)/(3-1)=(-6)/(2)=-3`

For now we have:

`y=-3x+b`

To find the y-intercept b, we have to replace (x,y) for one of the given points and solve for b. If we use point (1,2):

`\begin{gathered} y=-3x+b \\ \text{ replacing x = 1 and y = 2} \\ 2=-3\cdot1+b \\ 2=-3+b \\ b=2+3=5 \end{gathered}`

Answer:

The equation of the line is: y = -3x + 5