Question

Confused on what it is asking me to solve. Squared numbers are the answers

Answer 1

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Explanation:

Given: f(x)= x² -4x + 3

Find :-

a) f(1)

f(x)= x² -4x + 3

→ Substitute x with with 1:-

`\tt f(1)=\left(1\right)^2-4\left(1\right)+3`

`\tt f(1)=1-4\cdot \:1+3`

`\tt f(1)=1-4+3`

`\boxed{\tt f(1)=0}`

_______________________

b) f(3)

f(x)= x² -4x + 3

→ Substitute x with with 3:-

`\tt f(3)=\left(3\right)^2-4\left(3\right)+3`

`\tt f(3)=\left(3\right)^2-4\left(3\right)+3`

`\tt f(3)=3^2-4\cdot \:3+3`

`\tt f(3)=3^2-12+3`

`\tt f(3)=3^2-9`

`\tt f(3)=9-9`

`\boxed{\tt f(3)=0}`

_______________________

c) f(-1)

f(x)= x² -4x + 3

→ Substitute x with with -1:-

`\tt f(-1)=\left(-1\right)^2-4\left(-1\right)+3`

`\tt f(-1)=\left(-1\right)^2+4\cdot \:1+3`

`\tt f(-1)=1+4+3`

`\boxed{\tt f(-1)=8}`

_______________________

d) -f(1)

f(x)= x² -4x + 3

→ -f(1)

`\tt -f(1)=\left(1\right)^2-4\left(1\right)+3`

`\tt -f(1)=1-4\cdot \:1+3`

`\tt -f(1)=1-4+3`

`\boxed{\tt -f(1)=0}`

_____________________

Hope this helps! :)