Answer:
We are not given the ratio of cordial to water used in the mixture, so we can assume that the entire bottle of cordial is mixed with water to make the drink.
Since the bottle of cordial holds 800 ml of cordial, the total volume of the mixture would be 800 ml + volume of water added. Let's call the volume of water added x.
Therefore, the total volume of the drink would be 800 ml + x.
We are asked to find the minimum capacity of the container in liters, so we need to convert the total volume of the drink from milliliters to liters:
800 ml + x = (800 + x)/1000 liters
Now we can set up an inequality to find the minimum value of x that would make the total volume of the drink at least 1 liter:
800 ml + x ≥ 1000 ml
Simplifying this inequality, we get:
x ≥ 200 ml
Therefore, the minimum volume of water that needs to be added to the cordial to make a drink with a total volume of at least 1 liter is 200 ml.
So the minimum capacity of the container would be:
800 ml + 200 ml = 1000 ml = 1 liter
Therefore, the minimum capacity of the container in liters would be 1 liter.
Explanation: