Question

How many molecules are in 85g of silver nitrate?

Answer 1

3.0 × 10²³ molecules AgNO₃

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Chemistry

Atomic Structure

• Reading a Periodic Table
• Writing Compounds
• Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

• Using Dimensional Analysis

Step-by-step explanation:

Step 1: Define

85 g AgNO₃ (silver nitrate)

Step 2: Identify Conversions

Avogadro's Number

[PT] Molar Mass of Ag - 107.87 g/mol

[PT] Molar Mass of N - 14.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of AgNO₃ - 107.87 + 14.01 + 3(16.00) = 169.88 g/mol

Step 3: Convert

1. Set up:
   `\displaystyle 85 \ g \ AgNO_3((1 \ mol \ AgNO_3)/(169.88 \ g \ AgNO_3))((6.022 \cdot 10^(23) \ molecules \ AgNO_3)/(1 \ mol \ AgNO_3))`
2. Multiply/Divide:
   `\displaystyle 3.01313 \cdot 10^(23) \ molecules \ AgNO_3`

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

3.01313 × 10²³ molecules AgNO₃ ≈ 3.0 × 10²³ molecules AgNO₃