Question

At a county fair, 60% of the entries are livestock. Of those entries, 70% are sold at the auction. If

130 entries of livestock are sold at the auction, how many total entries were there at the fair?

Answer 1

Let's start by using algebra to solve the problem.

Let x be the total number of entries at the fair.

Given that 60% of the entries are livestock, we can write:

0.6x = number of livestock entries

Of those livestock entries, 70% are sold at the auction, which means:

0.7(0.6x) = 130

Simplifying the second equation, we get:

0.42x = 130

Solving for x, we can divide both sides by 0.42:

x = 309.52

Since we can't have a fractional number of entries, we can round up to the nearest whole number, giving us:

x = 310

Therefore, there were a total of 310 entries at the fair.

Explanation: