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I = 1/2MR^2 is rolling with a translational speed v along a horizontal surface without slipping. The work required to stop the disk is A. 1/2 mv^2 B. 1/2mv^2 + 1/2Iw^2 C. 1/2Iw^…
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I = 1/2MR^2 is rolling with a translational speed v along a horizontal surface without slipping. The work required to stop the disk is A. 1/2 mv^2 B. 1/2mv^2 + 1/2Iw^2 C. 1/2Iw^…
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Apr 12, 2024
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I = 1/2MR^2 is rolling with a translational speed v along a horizontal surface without slipping. The work required to stop the disk is
A. 1/2 mv^2
B. 1/2mv^2 + 1/2Iw^2
C. 1/2Iw^2
D. 1/2mv^2 - 1/2Iw^2
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Jon Onstott
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Answer:
B. 1/2mv^2 + 1/2Iw^2
Step-by-step explanation:
Sebnukem
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Apr 16, 2024
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Sebnukem
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