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Calculate the specific weight,

density and specific gravity Of I liter
of liquid which weighs 7 N

User Neha Tyagi
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1 Answer

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To calculate the specific weight, density, and specific gravity of a liquid that weighs 7 N in a 1 liter container, we need to know the acceleration due to gravity in the particular location where the measurement is being taken.

Assuming a standard acceleration due to gravity of 9.81 m/s^2:

Specific weight: The specific weight of a substance is its weight per unit volume.

Specific weight = weight / volume

In this case, the weight of the liquid is given as 7 N, and the volume is 1 liter, which is equivalent to 0.001 cubic meters. Therefore, the specific weight is:

Specific weight = 7 N / 0.001 m^3 = 7000 N/m^3

Density: The density of a substance is its mass per unit volume.

Density = mass / volume

We can calculate the mass of the liquid by dividing the weight by the acceleration due to gravity:

Mass = weight / acceleration due to gravity = 7 N / 9.81 m/s^2 = 0.714 kg

Therefore, the density of the liquid is:

Density = 0.714 kg / 0.001 m^3 = 714 kg/m^3

Specific gravity: The specific gravity of a substance is the ratio of its density to the density of a reference substance, typically water at 4°C.

Specific gravity = density of substance / density of water

The density of water at 4°C is approximately 1000 kg/m^3. Therefore, the specific gravity of the liquid is:

Specific gravity = 714 kg/m^3 / 1000 kg/m^3 = 0.714

User Impl
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