Question

A student prepares a solution by dissolving 20.0 g of aluminum chloride (AICI3) in

enough water to produce 500 mL of solution. What is the molarity of the solution?
Polici
0.160 M
0.320 M
0.080 M
0.040 M

A solution must be at a higher temperature than a pure solvent to boil. Which
colligative property can be employed to achieve this?

freezing-point depression
boiling-point elevation
vapor-pressure lowering

Which example will dissolve most slowly?
two sugar cubes
a tablespoon of ultrafine sugar
a tablespoon of table sugar
a tablespoon of coarse sugar

Answer 1

Answer:the second answer is boiling point elevation

the third answer is two sugar cubes

Step-by-step explanation:

Answer 2

Answer: b

Step-by-step explanation:

20.0g AlCl3/133.5715 g Alcl3 = .149732540 moles AlCl3

M=mol/L = 0.149732540/0.500=0.30

133.4515 (molar mass for AlCl3 from periodic table)