Question

a skateboarder who weighs 68kg is going down a ramp at the very bottom of the ramp they have 2400 J of kinetic energy calculate the speed in m/s to one decimal place

Answer 1

The skateboarder has 2400 J of kinetic energy. We can use the formula for kinetic energy to find the speed:

KE = 1/2 mv^2

KE = 1/2 (68 kg) (v^2)

2400 J = 1/2 (68 kg) (v^2)

2400 J = 34 kg v^2

2400 J / 34 kg = v^2

70.59 m/s = v^2