Answer:
The function y = 3(x - 2)^2 + 6 is in vertex form, which is y = a(x - h)^2 + k, where (h,k) is the vertex of the parabola.
In this case, the vertex is (2,6), and the coefficient "a" is 3, so we can write the equivalent function in standard form as follows:
y = 3(x - 2)^2 + 6
y = 3(x^2 - 4x + 4) + 6
y = 3x^2 - 12x + 18
Therefore, the equivalent function in standard form is y = 3x^2 - 12x + 18.