Question

A ball is thrown from a height of 154 feet with an initial downward velocity of 10 ft/s. The balls height (in feet) after t seconds is given by the following. h=154-10t-16t^2. how long after the ball is thrown does it hit the ground?

Answer 1

Explanation:

The ball hits the ground when h=0.

`0=154-10t-16t^(2)`

Solve for t. You can use the quadratic formula.

`t=\frac{-(-10)+-\sqrt{10^(2)(-16\cdot154) } }{2(-16)}`

`t=(5+-√(2489) )/(16) \\t=-3.43 t=2.81`

Time cannot be negative. So, the answer is t=2.81 seconds.

Answer 2

The answer is 164 feet