Question

Let ​f(x)=x2+6x+11​.

What is the minimum value of the function?

Enter your answer in the box. ​

Answer 1

Explanation:

The given function is a quadratic function with a positive leading coefficient, therefore it opens upwards and has a minimum value. To find the minimum value of the function, we can use the formula:

x = -b/2a

where a = 1 and b = 6 are the coefficients of the quadratic function.

x = -6/2(1) = -3

Substitute x = -3 into the function to find the minimum value:

f(-3) = (-3)^2 + 6(-3) + 11 = 2

Therefore, the minimum value of the function is 2.