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Let ​f(x)=x2+6x+11​.

What is the minimum value of the function?

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User Jeremija
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1 Answer

5 votes

Explanation:

The given function is a quadratic function with a positive leading coefficient, therefore it opens upwards and has a minimum value. To find the minimum value of the function, we can use the formula:

x = -b/2a

where a = 1 and b = 6 are the coefficients of the quadratic function.

x = -6/2(1) = -3

Substitute x = -3 into the function to find the minimum value:

f(-3) = (-3)^2 + 6(-3) + 11 = 2

Therefore, the minimum value of the function is 2.

User GabiMe
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